Base | Representation |
---|---|
bin | 1100000111010101100111… |
… | …1011010101100101100001 |
3 | 1202011101202210122100012121 |
4 | 3001311121323111211201 |
5 | 3221214233242441113 |
6 | 44155114431224241 |
7 | 2543232013344661 |
oct | 301653173254541 |
9 | 52141683570177 |
10 | 13320202312033 |
11 | 427607aa48041 |
12 | 15b1664978081 |
13 | 7581220783c6 |
14 | 3409b62741a1 |
15 | 181750725e8d |
hex | c1d59ed5961 |
13320202312033 has 4 divisors (see below), whose sum is σ = 13320385181460. Its totient is φ = 13320019442608.
The previous prime is 13320202312031. The next prime is 13320202312063. The reversal of 13320202312033 is 33021320202331.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 7101622722769 + 6218579589264 = 2664887^2 + 2493708^2 .
It is a cyclic number.
It is not a de Polignac number, because 13320202312033 - 21 = 13320202312031 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 13320202311989 and 13320202312007.
It is not an unprimeable number, because it can be changed into a prime (13320202312031) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 91325410 + ... + 91471147.
It is an arithmetic number, because the mean of its divisors is an integer number (3330096295365).
Almost surely, 213320202312033 is an apocalyptic number.
It is an amenable number.
13320202312033 is a deficient number, since it is larger than the sum of its proper divisors (182869427).
13320202312033 is an equidigital number, since it uses as much as digits as its factorization.
13320202312033 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 182869426.
The product of its (nonzero) digits is 3888, while the sum is 25.
Adding to 13320202312033 its reverse (33021320202331), we get a palindrome (46341522514364).
The spelling of 13320202312033 in words is "thirteen trillion, three hundred twenty billion, two hundred two million, three hundred twelve thousand, thirty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.072 sec. • engine limits •