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13320222011323 = 19767615340159
BaseRepresentation
bin1100000111010101101100…
…0110011110111110111011
31202011101211011201011112221
43001311123012132332323
53221214303313330243
644155120413344511
72543232342652213
oct301653306367673
952141734634487
1013320222011323
114276090082447
1215b166b498137
137581261849a6
143409b8b21243
15181752317bed
hexc1d5b19efbb

13320222011323 has 4 divisors (see below), whose sum is σ = 13387837351680. Its totient is φ = 13252606670968.

The previous prime is 13320222011321. The next prime is 13320222011389. The reversal of 13320222011323 is 32311022202331.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13320222011323 - 21 = 13320222011321 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13320222011321) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 33807669883 + ... + 33807670276.

It is an arithmetic number, because the mean of its divisors is an integer number (3346959337920).

Almost surely, 213320222011323 is an apocalyptic number.

13320222011323 is a deficient number, since it is larger than the sum of its proper divisors (67615340357).

13320222011323 is an equidigital number, since it uses as much as digits as its factorization.

13320222011323 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 67615340356.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 13320222011323 its reverse (32311022202331), we get a palindrome (45631244213654).

The spelling of 13320222011323 in words is "thirteen trillion, three hundred twenty billion, two hundred twenty-two million, eleven thousand, three hundred twenty-three".

Divisors: 1 197 67615340159 13320222011323