Base | Representation |
---|---|
bin | 1100000111010101101100… |
… | …0110100110000101110001 |
3 | 1202011101211011202122111002 |
4 | 3001311123012212011301 |
5 | 3221214303320243213 |
6 | 44155120414131345 |
7 | 2543232343133120 |
oct | 301653306460561 |
9 | 52141734678432 |
10 | 13320222040433 |
11 | 42760900a2300 |
12 | 15b166b4b0b55 |
13 | 758126195009 |
14 | 3409b8b2bab7 |
15 | 181752321658 |
hex | c1d5b1a6171 |
13320222040433 has 24 divisors (see below), whose sum is σ = 16733274155136. Its totient is φ = 10379125056960.
The previous prime is 13320222040421. The next prime is 13320222040469. The reversal of 13320222040433 is 33404022202331.
It is not a de Polignac number, because 13320222040433 - 210 = 13320222039409 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13320222040396 and 13320222040405.
It is not an unprimeable number, because it can be changed into a prime (13320222040633) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 36414341 + ... + 36778317.
It is an arithmetic number, because the mean of its divisors is an integer number (697219756464).
Almost surely, 213320222040433 is an apocalyptic number.
It is an amenable number.
13320222040433 is a deficient number, since it is larger than the sum of its proper divisors (3413052114703).
13320222040433 is a wasteful number, since it uses less digits than its factorization.
13320222040433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 407213 (or 407202 counting only the distinct ones).
The product of its (nonzero) digits is 20736, while the sum is 29.
Adding to 13320222040433 its reverse (33404022202331), we get a palindrome (46724244242764).
The spelling of 13320222040433 in words is "thirteen trillion, three hundred twenty billion, two hundred twenty-two million, forty thousand, four hundred thirty-three".
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