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133202320441 = 166380097607
BaseRepresentation
bin111110000001101111…
…0100001110000111001
3110201211002122222102121
41330003132201300321
54140244243223231
6141105312001241
712423610020361
oct1740336416071
9421732588377
10133202320441
1151544267953
1221995230221
13c73a4765b8
1466388d99a1
1536e906e311
hex1f037a1c39

133202320441 has 4 divisors (see below), whose sum is σ = 133282419712. Its totient is φ = 133122221172.

The previous prime is 133202320409. The next prime is 133202320453. The reversal of 133202320441 is 144023202331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 133202320441 - 25 = 133202320409 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (133202320841) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 40047141 + ... + 40050466.

It is an arithmetic number, because the mean of its divisors is an integer number (33320604928).

Almost surely, 2133202320441 is an apocalyptic number.

It is an amenable number.

133202320441 is a deficient number, since it is larger than the sum of its proper divisors (80099271).

133202320441 is an equidigital number, since it uses as much as digits as its factorization.

133202320441 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 80099270.

The product of its (nonzero) digits is 3456, while the sum is 25.

Adding to 133202320441 its reverse (144023202331), we get a palindrome (277225522772).

The spelling of 133202320441 in words is "one hundred thirty-three billion, two hundred two million, three hundred twenty thousand, four hundred forty-one".

Divisors: 1 1663 80097607 133202320441