13320300230113 has 4 divisors (see below), whose sum is σ = 13325521832128. Its totient is φ = 13315078628100.

The previous prime is 13320300230057. The next prime is 13320300230129. The reversal of 13320300230113 is 31103200302331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13320300230113 - 2²¹ = 13320298132961 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13320300200113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2610797181 + ... + 2610802282.

It is an arithmetic number, because the mean of its divisors is an integer number (3331380458032).

Almost surely, 2^{13320300230113} is an apocalyptic number.

It is an amenable number.

13320300230113 is a deficient number, since it is larger than the sum of its proper divisors (5221602015).

13320300230113 is an equidigital number, since it uses as much as digits as its factorization.

13320300230113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5221602014.

The product of its (nonzero) digits is 972, while the sum is 22.

Adding to 13320300230113 its reverse (31103200302331), we get a palindrome (44423500532444).

The spelling of 13320300230113 in words is "thirteen trillion, three hundred twenty billion, three hundred million, two hundred thirty thousand, one hundred thirteen".