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1332032102114 = 2795145150151
BaseRepresentation
bin10011011000100011010…
…011001101111011100010
311201100012121101211122112
4103120203103031323202
5133311000204231424
62455532130435322
7165143666024240
oct23304323157342
94640177354575
101332032102114
11473a0343965a
121961a6a32b42
13987c149660c
1448683847790
15249b115360e
hex136234cdee2

1332032102114 has 8 divisors (see below), whose sum is σ = 2283483603648. Its totient is φ = 570870900900.

The previous prime is 1332032102113. The next prime is 1332032102239. The reversal of 1332032102114 is 4112012302331.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a self number, because there is not a number n which added to its sum of digits gives 1332032102114.

It is not an unprimeable number, because it can be changed into a prime (1332032102113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 47572575062 + ... + 47572575089.

It is an arithmetic number, because the mean of its divisors is an integer number (285435450456).

Almost surely, 21332032102114 is an apocalyptic number.

1332032102114 is a gapful number since it is divisible by the number (14) formed by its first and last digit.

1332032102114 is a deficient number, since it is larger than the sum of its proper divisors (951451501534).

1332032102114 is an equidigital number, since it uses as much as digits as its factorization.

1332032102114 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 95145150160.

The product of its (nonzero) digits is 864, while the sum is 23.

Adding to 1332032102114 its reverse (4112012302331), we get a palindrome (5444044404445).

The spelling of 1332032102114 in words is "one trillion, three hundred thirty-two billion, thirty-two million, one hundred two thousand, one hundred fourteen".

Divisors: 1 2 7 14 95145150151 190290300302 666016051057 1332032102114