133204214121 has 8 divisors (see below), whose sum is σ = 193751584224. Its totient is φ = 80729826720.

The previous prime is 133204214093. The next prime is 133204214131. The reversal of 133204214121 is 121412402331.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 133204214121 - 2⁵ = 133204214089 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 133204214091 and 133204214100.

It is not an unprimeable number, because it can be changed into a prime (133204214131) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2018245636 + ... + 2018245701.

It is an arithmetic number, because the mean of its divisors is an integer number (24218948028).

Almost surely, 2^133204214121 is an apocalyptic number.

133204214121 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

133204214121 is a deficient number, since it is larger than the sum of its proper divisors (60547370103).

133204214121 is a wasteful number, since it uses less digits than its factorization.

133204214121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4036491351.

The product of its (nonzero) digits is 1152, while the sum is 24.

Adding to 133204214121 its reverse (121412402331), we get a palindrome (254616616452).

The spelling of 133204214121 in words is "one hundred thirty-three billion, two hundred four million, two hundred fourteen thousand, one hundred twenty-one".