Base | Representation |
---|---|
bin | 1100000111010110011110… |
… | …1111010001111001110001 |
3 | 1202011102100221122221120112 |
4 | 3001311213233101321301 |
5 | 3221220222103012431 |
6 | 44155153425551105 |
7 | 2543240526054050 |
oct | 301654757217161 |
9 | 52142327587515 |
10 | 13320434032241 |
11 | 4276189825946 |
12 | 15b170a4a5495 |
13 | 75815b08a65b |
14 | 3409d8d52397 |
15 | 181765c48c2b |
hex | c1d67bd1e71 |
13320434032241 has 32 divisors (see below), whose sum is σ = 16131418168320. Its totient is φ = 10737517593600.
The previous prime is 13320434032111. The next prime is 13320434032249. The reversal of 13320434032241 is 14223043402331.
It is a de Polignac number, because none of the positive numbers 2k-13320434032241 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13320434032198 and 13320434032207.
It is not an unprimeable number, because it can be changed into a prime (13320434032249) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1031705576 + ... + 1031718486.
It is an arithmetic number, because the mean of its divisors is an integer number (504106817760).
Almost surely, 213320434032241 is an apocalyptic number.
It is an amenable number.
13320434032241 is a deficient number, since it is larger than the sum of its proper divisors (2810984136079).
13320434032241 is a wasteful number, since it uses less digits than its factorization.
13320434032241 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 19025.
The product of its (nonzero) digits is 41472, while the sum is 32.
Adding to 13320434032241 its reverse (14223043402331), we get a palindrome (27543477434572).
The spelling of 13320434032241 in words is "thirteen trillion, three hundred twenty billion, four hundred thirty-four million, thirty-two thousand, two hundred forty-one".
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