1332100100101 has 4 divisors (see below), whose sum is σ = 1375071071104. Its totient is φ = 1289129129100.

The previous prime is 1332100100081. The next prime is 1332100100137. The reversal of 1332100100101 is 1010010012331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1332100100101 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1332100100161) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21485485455 + ... + 21485485516.

It is an arithmetic number, because the mean of its divisors is an integer number (343767767776).

Almost surely, 2^{1332100100101} is an apocalyptic number.

It is an amenable number.

1332100100101 is a deficient number, since it is larger than the sum of its proper divisors (42970971003).

1332100100101 is an equidigital number, since it uses as much as digits as its factorization.

1332100100101 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 42970971002.

The product of its (nonzero) digits is 18, while the sum is 13.

Adding to 1332100100101 its reverse (1010010012331), we get a palindrome (2342110112432).

The spelling of 1332100100101 in words is "one trillion, three hundred thirty-two billion, one hundred million, one hundred thousand, one hundred one".