13321240444441 has 4 divisors (see below), whose sum is σ = 13321418394384. Its totient is φ = 13321062494500.

The previous prime is 13321240444423. The next prime is 13321240444469. The reversal of 13321240444441 is 14444404212331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13321240444441 - 2¹³ = 13321240436249 is a prime.

It is a super-2 number, since 2×13321240444441² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 13321240444441.

It is not an unprimeable number, because it can be changed into a prime (13321240444741) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 88862635 + ... + 89012416.

It is an arithmetic number, because the mean of its divisors is an integer number (3330354598596).

Almost surely, 2^{13321240444441} is an apocalyptic number.

It is an amenable number.

13321240444441 is a deficient number, since it is larger than the sum of its proper divisors (177949943).

13321240444441 is an equidigital number, since it uses as much as digits as its factorization.

13321240444441 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 177949942.

The product of its (nonzero) digits is 147456, while the sum is 37.

Adding to 13321240444441 its reverse (14444404212331), we get a palindrome (27765644656772).

The spelling of 13321240444441 in words is "thirteen trillion, three hundred twenty-one billion, two hundred forty million, four hundred forty-four thousand, four hundred forty-one".