Base | Representation |
---|---|
bin | 1100000111011001011111… |
… | …0011011111111000000111 |
3 | 1202011111110011001221010101 |
4 | 3001312113303133320013 |
5 | 3221223400023210143 |
6 | 44155405434104531 |
7 | 2543266520335012 |
oct | 301662763377007 |
9 | 52144404057111 |
10 | 13321240444423 |
11 | 4276562a4629a |
12 | 15b18b457b147 |
13 | 758259177022 |
14 | 340a740aa379 |
15 | 1817b193ab4d |
hex | c1d97cdfe07 |
13321240444423 has 2 divisors, whose sum is σ = 13321240444424. Its totient is φ = 13321240444422.
The previous prime is 13321240444357. The next prime is 13321240444469. The reversal of 13321240444423 is 32444404212331.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13321240444423 - 229 = 13320703573511 is a prime.
It is a super-3 number, since 3×133212404444233 (a number of 40 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13321240444123) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6660620222211 + 6660620222212.
It is an arithmetic number, because the mean of its divisors is an integer number (6660620222212).
Almost surely, 213321240444423 is an apocalyptic number.
13321240444423 is a deficient number, since it is larger than the sum of its proper divisors (1).
13321240444423 is an equidigital number, since it uses as much as digits as its factorization.
13321240444423 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 221184, while the sum is 37.
Adding to 13321240444423 its reverse (32444404212331), we get a palindrome (45765644656754).
The spelling of 13321240444423 in words is "thirteen trillion, three hundred twenty-one billion, two hundred forty million, four hundred forty-four thousand, four hundred twenty-three".
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