Base | Representation |
---|---|
bin | 11110010010100110110100… |
… | …101000110100111001010101 |
3 | 122110200201012000211201120202 |
4 | 132102212310220310321111 |
5 | 114430134110443040313 |
6 | 1151200234254110245 |
7 | 40026554364403010 |
oct | 3622466450647125 |
9 | 573621160751522 |
10 | 133220031221333 |
11 | 394a2330649181 |
12 | 12b36b26aab385 |
13 | 59447973c0a34 |
14 | 24c7c53668377 |
15 | 106055aae8558 |
hex | 7929b4a34e55 |
133220031221333 has 4 divisors (see below), whose sum is σ = 152251464252960. Its totient is φ = 114188598189708.
The previous prime is 133220031221309. The next prime is 133220031221341. The reversal of 133220031221333 is 333122130022331.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 133220031221333 - 218 = 133220030959189 is a prime.
It is a super-2 number, since 2×1332200312213332 (a number of 29 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 133220031221296 and 133220031221305.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (133220031221353) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9515716515803 + ... + 9515716515816.
It is an arithmetic number, because the mean of its divisors is an integer number (38062866063240).
Almost surely, 2133220031221333 is an apocalyptic number.
It is an amenable number.
133220031221333 is a deficient number, since it is larger than the sum of its proper divisors (19031433031627).
133220031221333 is an equidigital number, since it uses as much as digits as its factorization.
133220031221333 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 19031433031626.
The product of its (nonzero) digits is 11664, while the sum is 29.
Adding to 133220031221333 its reverse (333122130022331), we get a palindrome (466342161243664).
The spelling of 133220031221333 in words is "one hundred thirty-three trillion, two hundred twenty billion, thirty-one million, two hundred twenty-one thousand, three hundred thirty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.082 sec. • engine limits •