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133220112000 = 273535947041
BaseRepresentation
bin111110000010010001…
…0011001011010000000
3110201212100010212212020
41330010202121122000
54140313322041000
6141111145201440
712424214160663
oct1740442313200
9421770125766
10133220112000
1151553309a18
122199b190280
13c741065751
14663b00b6da
1536ea8d5ba0
hex1f04899680

133220112000 has 256 divisors, whose sum is σ = 449119382400. Its totient is φ = 34922496000.

The previous prime is 133220111989. The next prime is 133220112013. The reversal of 133220112000 is 211022331.

133220112000 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is an unprimeable number.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 2808480 + ... + 2855520.

Almost surely, 2133220112000 is an apocalyptic number.

133220112000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 133220112000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (224559691200).

133220112000 is an abundant number, since it is smaller than the sum of its proper divisors (315899270400).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

133220112000 is an equidigital number, since it uses as much as digits as its factorization.

133220112000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 47132 (or 47110 counting only the distinct ones).

The product of its (nonzero) digits is 72, while the sum is 15.

Adding to 133220112000 its reverse (211022331), we get a palindrome (133431134331).

The spelling of 133220112000 in words is "one hundred thirty-three billion, two hundred twenty million, one hundred twelve thousand".