13322020304041 has 4 divisors (see below), whose sum is σ = 13334842268800. Its totient is φ = 13309198339284.

The previous prime is 13322020304039. The next prime is 13322020304051. The reversal of 13322020304041 is 14040302022331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13322020304041 - 2¹ = 13322020304039 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13322020303997 and 13322020304015.

It is not an unprimeable number, because it can be changed into a prime (13322020304051) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6410980821 + ... + 6410982898.

It is an arithmetic number, because the mean of its divisors is an integer number (3333710567200).

Almost surely, 2^{13322020304041} is an apocalyptic number.

It is an amenable number.

13322020304041 is a deficient number, since it is larger than the sum of its proper divisors (12821964759).

13322020304041 is a wasteful number, since it uses less digits than its factorization.

13322020304041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 12821964758.

The product of its (nonzero) digits is 3456, while the sum is 25.

Adding to 13322020304041 its reverse (14040302022331), we get a palindrome (27362322326372).

The spelling of 13322020304041 in words is "thirteen trillion, three hundred twenty-two billion, twenty million, three hundred four thousand, forty-one".