Base | Representation |
---|---|
bin | 1100000111100000001110… |
… | …1011111100100110011101 |
3 | 1202011200010021211102020122 |
4 | 3001320003223330212131 |
5 | 3221241101400414003 |
6 | 44200305211524325 |
7 | 2543362415623562 |
oct | 301700353744635 |
9 | 52150107742218 |
10 | 13323050404253 |
11 | 4277301692967 |
12 | 15b211a7596a5 |
13 | 758487143585 |
14 | 340ba6616869 |
15 | 18186a7b0238 |
hex | c1e03afc99d |
13323050404253 has 16 divisors (see below), whose sum is σ = 14357090571264. Its totient is φ = 12318100005120.
The previous prime is 13323050404201. The next prime is 13323050404273. The reversal of 13323050404253 is 35240405032331.
It is a cyclic number.
It is not a de Polignac number, because 13323050404253 - 28 = 13323050403997 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13323050404273) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 19590125 + ... + 20258802.
It is an arithmetic number, because the mean of its divisors is an integer number (897318160704).
Almost surely, 213323050404253 is an apocalyptic number.
It is an amenable number.
13323050404253 is a deficient number, since it is larger than the sum of its proper divisors (1034040167011).
13323050404253 is a wasteful number, since it uses less digits than its factorization.
13323050404253 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 39849292.
The product of its (nonzero) digits is 129600, while the sum is 35.
Adding to 13323050404253 its reverse (35240405032331), we get a palindrome (48563455436584).
The spelling of 13323050404253 in words is "thirteen trillion, three hundred twenty-three billion, fifty million, four hundred four thousand, two hundred fifty-three".
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