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13323120202123 = 15139880052857
BaseRepresentation
bin1100000111100000011111…
…0110001101000110001011
31202011200022011011111220221
43001320013312031012023
53221241222232431443
644200320143530511
72543364224116114
oct301700766150613
952150264144827
1013323120202123
114277338026056
1215b2139bb9a37
137584987410a4
14340bb19c520b
1518187199aeed
hexc1e07d8d18b

13323120202123 has 4 divisors (see below), whose sum is σ = 13324000270120. Its totient is φ = 13322240134128.

The previous prime is 13323120202121. The next prime is 13323120202163. The reversal of 13323120202123 is 32120202132331.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13323120202123 - 21 = 13323120202121 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13323120202121) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 440011290 + ... + 440041567.

It is an arithmetic number, because the mean of its divisors is an integer number (3331000067530).

Almost surely, 213323120202123 is an apocalyptic number.

13323120202123 is a deficient number, since it is larger than the sum of its proper divisors (880067997).

13323120202123 is an equidigital number, since it uses as much as digits as its factorization.

13323120202123 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 880067996.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 13323120202123 its reverse (32120202132331), we get a palindrome (45443322334454).

The spelling of 13323120202123 in words is "thirteen trillion, three hundred twenty-three billion, one hundred twenty million, two hundred two thousand, one hundred twenty-three".

Divisors: 1 15139 880052857 13323120202123