Base | Representation |
---|---|
bin | 111110000010101000… |
… | …0001101011010101101 |
3 | 110201220011202000211011 |
4 | 1330011100031122231 |
5 | 4140324410342032 |
6 | 141112254425221 |
7 | 12424421230105 |
oct | 1740520153255 |
9 | 421804660734 |
10 | 133232121517 |
11 | 5155a071940 |
12 | 219a3202211 |
13 | c7436abb81 |
14 | 663c856205 |
15 | 36eb9a9247 |
hex | 1f0540d6ad |
133232121517 has 4 divisors (see below), whose sum is σ = 145344132576. Its totient is φ = 121120110460.
The previous prime is 133232121511. The next prime is 133232121527. The reversal of 133232121517 is 715121232331.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-133232121517 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (133232121511) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6056005513 + ... + 6056005534.
It is an arithmetic number, because the mean of its divisors is an integer number (36336033144).
Almost surely, 2133232121517 is an apocalyptic number.
It is an amenable number.
133232121517 is a deficient number, since it is larger than the sum of its proper divisors (12112011059).
133232121517 is a wasteful number, since it uses less digits than its factorization.
133232121517 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 12112011058.
The product of its digits is 7560, while the sum is 31.
Adding to 133232121517 its reverse (715121232331), we get a palindrome (848353353848).
The spelling of 133232121517 in words is "one hundred thirty-three billion, two hundred thirty-two million, one hundred twenty-one thousand, five hundred seventeen".
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