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133245031147 = 139995243053
BaseRepresentation
bin111110000011000000…
…1011101001011101011
3110201221002000220111121
41330012001131023223
54140341211444042
6141113435240111
712424636035364
oct1740601351353
9421832026447
10133245031147
115156638a058
12219a75a9037
13c74627bbc7
146640456b6b
1536ecba9367
hex1f0605d2eb

133245031147 has 4 divisors (see below), whose sum is σ = 133340275600. Its totient is φ = 133149786696.

The previous prime is 133245031097. The next prime is 133245031151. The reversal of 133245031147 is 741130542331.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-133245031147 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (133245031247) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 47620128 + ... + 47622925.

It is an arithmetic number, because the mean of its divisors is an integer number (33335068900).

Almost surely, 2133245031147 is an apocalyptic number.

133245031147 is a deficient number, since it is larger than the sum of its proper divisors (95244453).

133245031147 is an equidigital number, since it uses as much as digits as its factorization.

133245031147 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 95244452.

The product of its (nonzero) digits is 30240, while the sum is 34.

Adding to 133245031147 its reverse (741130542331), we get a palindrome (874375573478).

The spelling of 133245031147 in words is "one hundred thirty-three billion, two hundred forty-five million, thirty-one thousand, one hundred forty-seven".

Divisors: 1 1399 95243053 133245031147