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13324504403557 = 50094726598631
BaseRepresentation
bin1100000111100101101001…
…0110100000111001100101
31202011210212121210020022201
43001321122112200321211
53221302041111403212
644201105352054501
72543443432461604
oct301713226407145
952153777706281
1013324504403557
114277988404086
1215b2465694431
1375865944a8a9
14340ca3783a3b
1518190326eb57
hexc1e5a5a0e65

13324504403557 has 4 divisors (see below), whose sum is σ = 13324531503136. Its totient is φ = 13324477303980.

The previous prime is 13324504403527. The next prime is 13324504403593. The reversal of 13324504403557 is 75530440542331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13324504403557 - 27 = 13324504403429 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13324504403527) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12798369 + ... + 13800262.

It is an arithmetic number, because the mean of its divisors is an integer number (3331132875784).

Almost surely, 213324504403557 is an apocalyptic number.

It is an amenable number.

13324504403557 is a deficient number, since it is larger than the sum of its proper divisors (27099579).

13324504403557 is an equidigital number, since it uses as much as digits as its factorization.

13324504403557 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 27099578.

The product of its (nonzero) digits is 3024000, while the sum is 46.

Adding to 13324504403557 its reverse (75530440542331), we get a palindrome (88854944945888).

The spelling of 13324504403557 in words is "thirteen trillion, three hundred twenty-four billion, five hundred four million, four hundred three thousand, five hundred fifty-seven".

Divisors: 1 500947 26598631 13324504403557