Base | Representation |
---|---|
bin | 10011011000111100010… |
… | …110010001111001100001 |
3 | 11201101021220010220001221 |
4 | 103120330112101321201 |
5 | 133312330244211301 |
6 | 2500041541455041 |
7 | 165160260655501 |
oct | 23307426217141 |
9 | 4641256126057 |
10 | 1332452335201 |
11 | 4740a9673a29 |
12 | 1962a3711481 |
13 | 9885a570450 |
14 | 486c3597a01 |
15 | 249d7eb1da1 |
hex | 1363c591e61 |
1332452335201 has 4 divisors (see below), whose sum is σ = 1434948668692. Its totient is φ = 1229956001712.
The previous prime is 1332452335199. The next prime is 1332452335213. The reversal of 1332452335201 is 1025332542331.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 888496645201 + 443955690000 = 942601^2 + 666300^2 .
It is a cyclic number.
It is not a de Polignac number, because 1332452335201 - 21 = 1332452335199 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1332452330201) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 51248166726 + ... + 51248166751.
It is an arithmetic number, because the mean of its divisors is an integer number (358737167173).
Almost surely, 21332452335201 is an apocalyptic number.
It is an amenable number.
1332452335201 is a deficient number, since it is larger than the sum of its proper divisors (102496333491).
1332452335201 is a wasteful number, since it uses less digits than its factorization.
1332452335201 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 102496333490.
The product of its (nonzero) digits is 64800, while the sum is 34.
Adding to 1332452335201 its reverse (1025332542331), we get a palindrome (2357784877532).
The spelling of 1332452335201 in words is "one trillion, three hundred thirty-two billion, four hundred fifty-two million, three hundred thirty-five thousand, two hundred one".
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