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133250014455133 = 637003209182711
BaseRepresentation
bin11110010011000010101111…
…110001110010010101011101
3122110210120120121120211001111
4132103002233301302111131
5114431132012200031013
61151222113410542021
740031665401601552
oct3623025761622535
9573716517524044
10133250014455133
1139504017380544
1212b408b4297911
1359475651655b4
1424c949978aa29
15106121300e73d
hex7930afc7255d

133250014455133 has 4 divisors (see below), whose sum is σ = 133250224274848. Its totient is φ = 133249804635420.

The previous prime is 133250014455059. The next prime is 133250014455143. The reversal of 133250014455133 is 331554410052331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-133250014455133 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (133250014455143) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 103954353 + ... + 105228358.

It is an arithmetic number, because the mean of its divisors is an integer number (33312556068712).

Almost surely, 2133250014455133 is an apocalyptic number.

It is an amenable number.

133250014455133 is a deficient number, since it is larger than the sum of its proper divisors (209819715).

133250014455133 is an equidigital number, since it uses as much as digits as its factorization.

133250014455133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 209819714.

The product of its (nonzero) digits is 324000, while the sum is 40.

The spelling of 133250014455133 in words is "one hundred thirty-three trillion, two hundred fifty billion, fourteen million, four hundred fifty-five thousand, one hundred thirty-three".

Divisors: 1 637003 209182711 133250014455133