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133253544001 = 199669615799
BaseRepresentation
bin111110000011010000…
…1111011100001000001
3110201221200001101221111
41330012201323201001
54140400401402001
6141114341523321
712425101302244
oct1740641734101
9421850041844
10133253544001
1151570173976
12219aa413541
13c747c6c8b6
14664163125b
1536ed7db851
hex1f0687b841

133253544001 has 4 divisors (see below), whose sum is σ = 133923160000. Its totient is φ = 132583928004.

The previous prime is 133253543987. The next prime is 133253544007. The reversal of 133253544001 is 100445352331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 133253544001 - 225 = 133219989569 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (133253544007) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 334807701 + ... + 334808098.

It is an arithmetic number, because the mean of its divisors is an integer number (33480790000).

Almost surely, 2133253544001 is an apocalyptic number.

It is an amenable number.

133253544001 is a deficient number, since it is larger than the sum of its proper divisors (669615999).

133253544001 is an equidigital number, since it uses as much as digits as its factorization.

133253544001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 669615998.

The product of its (nonzero) digits is 21600, while the sum is 31.

Adding to 133253544001 its reverse (100445352331), we get a palindrome (233698896332).

The spelling of 133253544001 in words is "one hundred thirty-three billion, two hundred fifty-three million, five hundred forty-four thousand, one".

Divisors: 1 199 669615799 133253544001