Base | Representation |
---|---|
bin | 11000110100100000… |
… | …11000010110010111 |
3 | 1021101200002122012120 |
4 | 30122100120112113 |
5 | 204242300403133 |
6 | 10042133351023 |
7 | 651134030004 |
oct | 143220302627 |
9 | 37350078176 |
10 | 13325403543 |
11 | 571892aa01 |
12 | 26ba798473 |
13 | 134492558a |
14 | 905a728ab |
15 | 52ecccab3 |
hex | 31a418597 |
13325403543 has 4 divisors (see below), whose sum is σ = 17767204728. Its totient is φ = 8883602360.
The previous prime is 13325403493. The next prime is 13325403569. The reversal of 13325403543 is 34530452331.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13325403543 - 221 = 13323306391 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13325403583) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2220900588 + ... + 2220900593.
It is an arithmetic number, because the mean of its divisors is an integer number (4441801182).
Almost surely, 213325403543 is an apocalyptic number.
13325403543 is a deficient number, since it is larger than the sum of its proper divisors (4441801185).
13325403543 is an equidigital number, since it uses as much as digits as its factorization.
13325403543 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4441801184.
The product of its (nonzero) digits is 64800, while the sum is 33.
Adding to 13325403543 its reverse (34530452331), we get a palindrome (47855855874).
The spelling of 13325403543 in words is "thirteen billion, three hundred twenty-five million, four hundred three thousand, five hundred forty-three".
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