Base | Representation |
---|---|
bin | 1100000111101000111111… |
… | …1111001010010110001111 |
3 | 1202011220012100000020200121 |
4 | 3001322033333022112033 |
5 | 3221310411442022120 |
6 | 44201334535005411 |
7 | 2543504640165235 |
oct | 301721777122617 |
9 | 52156170006617 |
10 | 13325404251535 |
11 | 42782aa3421a2 |
12 | 15b2676b09867 |
13 | 7587709c000c |
14 | 340d4b0a0955 |
15 | 18195726b5aa |
hex | c1e8ffca58f |
13325404251535 has 8 divisors (see below), whose sum is σ = 16015199920416. Its totient is φ = 10643846855520.
The previous prime is 13325404251529. The next prime is 13325404251539. The reversal of 13325404251535 is 53515240452331.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 13325404251535 - 217 = 13325404120463 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 13325404251491 and 13325404251500.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13325404251539) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2059564656 + ... + 2059571125.
It is an arithmetic number, because the mean of its divisors is an integer number (2001899990052).
Almost surely, 213325404251535 is an apocalyptic number.
13325404251535 is a deficient number, since it is larger than the sum of its proper divisors (2689795668881).
13325404251535 is an equidigital number, since it uses as much as digits as its factorization.
13325404251535 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4119136433.
The product of its (nonzero) digits is 1080000, while the sum is 43.
The spelling of 13325404251535 in words is "thirteen trillion, three hundred twenty-five billion, four hundred four million, two hundred fifty-one thousand, five hundred thirty-five".
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