Base | Representation |
---|---|
bin | 1100000111101001000001… |
… | …1101111101011100001111 |
3 | 1202011220012220012102120211 |
4 | 3001322100131331130033 |
5 | 3221310421023401020 |
6 | 44201335424023251 |
7 | 2543505065622361 |
oct | 301722035753417 |
9 | 52156186172524 |
10 | 13325412325135 |
11 | 4278303956a99 |
12 | 15b2679761b27 |
13 | 758772588ab1 |
14 | 340d4c1a2d31 |
15 | 181957d1385a |
hex | c1e9077d70f |
13325412325135 has 4 divisors (see below), whose sum is σ = 15990494790168. Its totient is φ = 10660329860104.
The previous prime is 13325412325129. The next prime is 13325412325157. The reversal of 13325412325135 is 53152321452331.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13325412325135 - 217 = 13325412194063 is a prime.
It is a super-2 number, since 2×133254123251352 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1332541232509 + ... + 1332541232518.
It is an arithmetic number, because the mean of its divisors is an integer number (3997623697542).
Almost surely, 213325412325135 is an apocalyptic number.
13325412325135 is a deficient number, since it is larger than the sum of its proper divisors (2665082465033).
13325412325135 is an equidigital number, since it uses as much as digits as its factorization.
13325412325135 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2665082465032.
The product of its digits is 324000, while the sum is 40.
Adding to 13325412325135 its reverse (53152321452331), we get a palindrome (66477733777466).
The spelling of 13325412325135 in words is "thirteen trillion, three hundred twenty-five billion, four hundred twelve million, three hundred twenty-five thousand, one hundred thirty-five".
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