Base | Representation |
---|---|
bin | 1100000111101001100011… |
… | …0100101101001011000111 |
3 | 1202011220120122222022221210 |
4 | 3001322120310231023013 |
5 | 3221311212420134133 |
6 | 44201401352342503 |
7 | 2543511420263535 |
oct | 301723064551307 |
9 | 52156518868853 |
10 | 13325552505543 |
11 | 4278375aa1673 |
12 | 15b26b86a4a33 |
13 | 75879562a295 |
14 | 340d62a53155 |
15 | 1819652a3763 |
hex | c1e98d2d2c7 |
13325552505543 has 16 divisors (see below), whose sum is σ = 17994126471680. Its totient is φ = 8770362846336.
The previous prime is 13325552505533. The next prime is 13325552505619. The reversal of 13325552505543 is 34550525552331.
13325552505543 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 13325552505543 - 25 = 13325552505511 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 13325552505492 and 13325552505501.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13325552505533) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 489730 + ... + 5185647.
It is an arithmetic number, because the mean of its divisors is an integer number (1124632904480).
Almost surely, 213325552505543 is an apocalyptic number.
13325552505543 is a deficient number, since it is larger than the sum of its proper divisors (4668573966137).
13325552505543 is an equidigital number, since it uses as much as digits as its factorization.
13325552505543 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5685366.
The product of its (nonzero) digits is 6750000, while the sum is 48.
The spelling of 13325552505543 in words is "thirteen trillion, three hundred twenty-five billion, five hundred fifty-two million, five hundred five thousand, five hundred forty-three".
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