Base | Representation |
---|---|
bin | 11110010011000111111001… |
… | …001010111000111110100001 |
3 | 122110211002211202021011201211 |
4 | 132103013321022320332201 |
5 | 114431224321412140001 |
6 | 1151224430022230121 |
7 | 40032252344336341 |
oct | 3623077112707641 |
9 | 573732752234654 |
10 | 133255540740001 |
11 | 395063a2868119 |
12 | 12b41996b85341 |
13 | 5947c36050244 |
14 | 24c98616c6d21 |
15 | 1061438272351 |
hex | 7931f92b8fa1 |
133255540740001 has 16 divisors (see below), whose sum is σ = 133719791103360. Its totient is φ = 132792216013440.
The previous prime is 133255540739947. The next prime is 133255540740031. The reversal of 133255540740001 is 100047045552331.
It is a cyclic number.
It is not a de Polignac number, because 133255540740001 - 27 = 133255540739873 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (133255540740031) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1016275621 + ... + 1016406733.
It is an arithmetic number, because the mean of its divisors is an integer number (8357486943960).
Almost surely, 2133255540740001 is an apocalyptic number.
It is an amenable number.
133255540740001 is a deficient number, since it is larger than the sum of its proper divisors (464250363359).
133255540740001 is a wasteful number, since it uses less digits than its factorization.
133255540740001 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 134616.
The product of its (nonzero) digits is 252000, while the sum is 40.
The spelling of 133255540740001 in words is "one hundred thirty-three trillion, two hundred fifty-five billion, five hundred forty million, seven hundred forty thousand, one".
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