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133255540740000 = 2535471741455201
BaseRepresentation
bin11110010011000111111001…
…001010111000111110100000
3122110211002211202021011201210
4132103013321022320332200
5114431224321412140000
61151224430022230120
740032252344336340
oct3623077112707640
9573732752234653
10133255540740000
11395063a2868118
1212b41996b85340
135947c36050243
1424c98616c6d20
151061438272350
hex7931f92b8fa0

133255540740000 has 960 divisors, whose sum is σ = 541835578513152. Its totient is φ = 27967488000000.

The previous prime is 133255540739947. The next prime is 133255540740031. The reversal of 133255540740000 is 47045552331.

It is an unprimeable number.

It is a polite number, since it can be written in 159 ways as a sum of consecutive naturals, for example, 292512400 + ... + 292967600.

Almost surely, 2133255540740000 is an apocalyptic number.

133255540740000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 133255540740000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (270917789256576).

133255540740000 is an abundant number, since it is smaller than the sum of its proper divisors (408580037773152).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

133255540740000 is a wasteful number, since it uses less digits than its factorization.

133255540740000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 455299 (or 455276 counting only the distinct ones).

The product of its (nonzero) digits is 252000, while the sum is 39.

The spelling of 133255540740000 in words is "one hundred thirty-three trillion, two hundred fifty-five billion, five hundred forty million, seven hundred forty thousand".