Search a number
-
+
133255662653051 = 207367642607853
BaseRepresentation
bin11110010011001000000000…
…011011111100111001111011
3122110211010011020122222222222
4132103020000123330321323
5114431230044114344201
61151224450055234255
740032255354516101
oct3623100033747173
9573733136588888
10133255662653051
1139506455666204
1212b41a0b97898b
135947c55396b43
1424c987397dc71
151061443d0491b
hex7932006fce7b

133255662653051 has 4 divisors (see below), whose sum is σ = 133256305468272. Its totient is φ = 133255019837832.

The previous prime is 133255662652993. The next prime is 133255662653077. The reversal of 133255662653051 is 150356266552331.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 133255662653051 - 246 = 62886918475387 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 133255662652984 and 133255662653002.

It is not an unprimeable number, because it can be changed into a prime (133255662653551) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 321096560 + ... + 321511293.

It is an arithmetic number, because the mean of its divisors is an integer number (33314076367068).

Almost surely, 2133255662653051 is an apocalyptic number.

133255662653051 is a deficient number, since it is larger than the sum of its proper divisors (642815221).

133255662653051 is an equidigital number, since it uses as much as digits as its factorization.

133255662653051 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 642815220.

The product of its (nonzero) digits is 14580000, while the sum is 53.

The spelling of 133255662653051 in words is "one hundred thirty-three trillion, two hundred fifty-five billion, six hundred sixty-two million, six hundred fifty-three thousand, fifty-one".

Divisors: 1 207367 642607853 133255662653051