Base | Representation |
---|---|
bin | 111110000011011110… |
… | …0001111010000110111 |
3 | 110201222011000210100020 |
4 | 1330012330033100313 |
5 | 4140404133100011 |
6 | 141115145420223 |
7 | 12425214025113 |
oct | 1740674172067 |
9 | 421864023306 |
10 | 133260440631 |
11 | 5157405446a |
12 | 219b079a673 |
13 | c749515a46 |
14 | 6642508743 |
15 | 36ee200006 |
hex | 1f06f0f437 |
133260440631 has 4 divisors (see below), whose sum is σ = 177680587512. Its totient is φ = 88840293752.
The previous prime is 133260440617. The next prime is 133260440707. The reversal of 133260440631 is 136044062331.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 133260440631 - 226 = 133193331767 is a prime.
It is a super-2 number, since 2×1332604406312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 133260440592 and 133260440601.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (133260442631) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22210073436 + ... + 22210073441.
It is an arithmetic number, because the mean of its divisors is an integer number (44420146878).
Almost surely, 2133260440631 is an apocalyptic number.
133260440631 is a deficient number, since it is larger than the sum of its proper divisors (44420146881).
133260440631 is an equidigital number, since it uses as much as digits as its factorization.
133260440631 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 44420146880.
The product of its (nonzero) digits is 31104, while the sum is 33.
The spelling of 133260440631 in words is "one hundred thirty-three billion, two hundred sixty million, four hundred forty thousand, six hundred thirty-one".
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