13326114023 has 4 divisors (see below), whose sum is σ = 13458055848. Its totient is φ = 13194172200.

The previous prime is 13326114013. The next prime is 13326114029. The reversal of 13326114023 is 32041162331.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 32041162331 = 101 ⋅317239231.

It is a cyclic number.

It is not a de Polignac number, because 13326114023 - 2¹⁰ = 13326112999 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13326113983 and 13326114001.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13326114029) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 65970761 + ... + 65970962.

It is an arithmetic number, because the mean of its divisors is an integer number (3364513962).

Almost surely, 2^13326114023 is an apocalyptic number.

13326114023 is a deficient number, since it is larger than the sum of its proper divisors (131941825).

13326114023 is a wasteful number, since it uses less digits than its factorization.

13326114023 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 131941824.

The product of its (nonzero) digits is 2592, while the sum is 26.

Adding to 13326114023 its reverse (32041162331), we get a palindrome (45367276354).

The spelling of 13326114023 in words is "thirteen billion, three hundred twenty-six million, one hundred fourteen thousand, twenty-three".