Base | Representation |
---|---|
bin | 1100000111111010001100… |
… | …0110111000111111101101 |
3 | 1202012100010000101011201101 |
4 | 3001332203012320333231 |
5 | 3221344340110341023 |
6 | 44203420542443101 |
7 | 2544030215411665 |
oct | 301764306707755 |
9 | 52170100334641 |
10 | 13330020012013 |
11 | 427a258869381 |
12 | 15b3544893491 |
13 | 759028067b33 |
14 | 3412681011a5 |
15 | 181b275c41ad |
hex | c1fa31b8fed |
13330020012013 has 4 divisors (see below), whose sum is σ = 13388742567360. Its totient is φ = 13271297456668.
The previous prime is 13330020012011. The next prime is 13330020012031. The reversal of 13330020012013 is 31021002003331.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 13330020012013 - 21 = 13330020012011 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13330020012011) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 29361277333 + ... + 29361277786.
It is an arithmetic number, because the mean of its divisors is an integer number (3347185641840).
Almost surely, 213330020012013 is an apocalyptic number.
It is an amenable number.
13330020012013 is a deficient number, since it is larger than the sum of its proper divisors (58722555347).
13330020012013 is an equidigital number, since it uses as much as digits as its factorization.
13330020012013 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 58722555346.
The product of its (nonzero) digits is 324, while the sum is 19.
Adding to 13330020012013 its reverse (31021002003331), we get a palindrome (44351022015344).
The spelling of 13330020012013 in words is "thirteen trillion, three hundred thirty billion, twenty million, twelve thousand, thirteen".
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