Base | Representation |
---|---|
bin | 111110000100101111… |
… | …1110001101111010001 |
3 | 110202002010200211212021 |
4 | 1330021133301233101 |
5 | 4141001121430223 |
6 | 141123320331441 |
7 | 12426244310404 |
oct | 1741137615721 |
9 | 422063624767 |
10 | 133303311313 |
11 | 51596275887 |
12 | 21a03013b81 |
13 | c755376103 |
14 | 66480a7d3b |
15 | 3702d6c65d |
hex | 1f097f1bd1 |
133303311313 has 4 divisors (see below), whose sum is σ = 133327417968. Its totient is φ = 133279204660.
The previous prime is 133303311283. The next prime is 133303311319. The reversal of 133303311313 is 313113303331.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 313113303331 = 647 ⋅483946373.
It is a cyclic number.
It is not a de Polignac number, because 133303311313 - 221 = 133301214161 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (133303311319) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12045031 + ... + 12056092.
It is an arithmetic number, because the mean of its divisors is an integer number (33331854492).
Almost surely, 2133303311313 is an apocalyptic number.
It is an amenable number.
133303311313 is a deficient number, since it is larger than the sum of its proper divisors (24106655).
133303311313 is an equidigital number, since it uses as much as digits as its factorization.
133303311313 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 24106654.
The product of its (nonzero) digits is 2187, while the sum is 25.
Adding to 133303311313 its reverse (313113303331), we get a palindrome (446416614644).
The spelling of 133303311313 in words is "one hundred thirty-three billion, three hundred three million, three hundred eleven thousand, three hundred thirteen".
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