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13330443101 = 115511154051
BaseRepresentation
bin11000110101000111…
…00110101101011101
31021102000120200011212
430122203212231131
5204300043134401
610042433354205
7651224616413
oct143243465535
937360520155
1013330443101
115720762228
122700408965
13134599b371
149065c52b3
15530475dbb
hex31a8e6b5d

13330443101 has 4 divisors (see below), whose sum is σ = 13331608704. Its totient is φ = 13329277500.

The previous prime is 13330442989. The next prime is 13330443127. The reversal of 13330443101 is 10134403331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13330443101 - 222 = 13326248797 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13330443151) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 565475 + ... + 588576.

It is an arithmetic number, because the mean of its divisors is an integer number (3332902176).

Almost surely, 213330443101 is an apocalyptic number.

It is an amenable number.

13330443101 is a deficient number, since it is larger than the sum of its proper divisors (1165603).

13330443101 is a wasteful number, since it uses less digits than its factorization.

13330443101 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1165602.

The product of its (nonzero) digits is 1296, while the sum is 23.

Adding to 13330443101 its reverse (10134403331), we get a palindrome (23464846432).

The spelling of 13330443101 in words is "thirteen billion, three hundred thirty million, four hundred forty-three thousand, one hundred one".

Divisors: 1 11551 1154051 13330443101