1333101000113 has 32 divisors (see below), whose sum is σ = 1425128826240. Its totient is φ = 1242662400000.

The previous prime is 1333101000059. The next prime is 1333101000137. The reversal of 1333101000113 is 3110001013331.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1333101000113 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (17).

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1333101000091 and 1333101000100.

It is not an unprimeable number, because it can be changed into a prime (1333101000613) by changing a digit.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 828526853 + ... + 828528461.

It is an arithmetic number, because the mean of its divisors is an integer number (44535275820).

Almost surely, 2^{1333101000113} is an apocalyptic number.

It is an amenable number.

1333101000113 is a deficient number, since it is larger than the sum of its proper divisors (92027826127).

1333101000113 is a wasteful number, since it uses less digits than its factorization.

1333101000113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2849.

The product of its (nonzero) digits is 81, while the sum is 17.

Adding to 1333101000113 its reverse (3110001013331), we get a palindrome (4443102013444).

The spelling of 1333101000113 in words is "one trillion, three hundred thirty-three billion, one hundred one million, one hundred thirteen", and thus it is an aban number.