13331204231 has 4 divisors (see below), whose sum is σ = 13334599464. Its totient is φ = 13327809000.

The previous prime is 13331204219. The next prime is 13331204261. The reversal of 13331204231 is 13240213331.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 13240213331 = 4817 ⋅2748643.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13331204231 is a prime.

It is a super-2 number, since 2×13331204231² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13331204197 and 13331204206.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13331204261) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1691720 + ... + 1699581.

It is an arithmetic number, because the mean of its divisors is an integer number (3333649866).

Almost surely, 2^13331204231 is an apocalyptic number.

13331204231 is a deficient number, since it is larger than the sum of its proper divisors (3395233).

13331204231 is an equidigital number, since it uses as much as digits as its factorization.

13331204231 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3395232.

The product of its (nonzero) digits is 1296, while the sum is 23.

Adding to 13331204231 its reverse (13240213331), we get a palindrome (26571417562).

The spelling of 13331204231 in words is "thirteen billion, three hundred thirty-one million, two hundred four thousand, two hundred thirty-one".