13331224003 has 4 divisors (see below), whose sum is σ = 13468659400. Its totient is φ = 13193788608.

The previous prime is 13331224001. The next prime is 13331224013. The reversal of 13331224003 is 30042213331.

13331224003 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13331224003 - 2¹ = 13331224001 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13331224001) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 68717553 + ... + 68717746.

It is an arithmetic number, because the mean of its divisors is an integer number (3367164850).

Almost surely, 2^13331224003 is an apocalyptic number.

13331224003 is a deficient number, since it is larger than the sum of its proper divisors (137435397).

13331224003 is an equidigital number, since it uses as much as digits as its factorization.

13331224003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 137435396.

The product of its (nonzero) digits is 1296, while the sum is 22.

Adding to 13331224003 its reverse (30042213331), we get a palindrome (43373437334).

The spelling of 13331224003 in words is "thirteen billion, three hundred thirty-one million, two hundred twenty-four thousand, three".