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133312534522042 = 2164881404268941
BaseRepresentation
bin11110010011111100111110…
…010000111010100010111010
3122111000112221202010021201011
4132103330332100322202322
5114433143032314201132
61151310533300544134
740036340611443241
oct3623747620724272
9574015852107634
10133312534522042
113952858a318127
1212b50a420b204a
135950419a29925
1424cc50abd5958
151062b71b03b47
hex793f3e43a8ba

133312534522042 has 8 divisors (see below), whose sum is σ = 199970015084532. Its totient is φ = 66655862827200.

The previous prime is 133312534522007. The next prime is 133312534522043. The reversal of 133312534522042 is 240225435213331.

It can be written as a sum of positive squares in 2 ways, for example, as 127914946382601 + 5397588139441 = 11309949^2 + 2323271^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a junction number, because it is equal to n+sod(n) for n = 133312534521986 and 133312534522004.

It is not an unprimeable number, because it can be changed into a prime (133312534522043) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 201804709 + ... + 202464232.

Almost surely, 2133312534522042 is an apocalyptic number.

133312534522042 is a deficient number, since it is larger than the sum of its proper divisors (66657480562490).

133312534522042 is a wasteful number, since it uses less digits than its factorization.

133312534522042 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 404433824.

The product of its (nonzero) digits is 518400, while the sum is 40.

Adding to 133312534522042 its reverse (240225435213331), we get a palindrome (373537969735373).

The spelling of 133312534522042 in words is "one hundred thirty-three trillion, three hundred twelve billion, five hundred thirty-four million, five hundred twenty-two thousand, forty-two".

Divisors: 1 2 164881 329762 404268941 808537882 66656267261021 133312534522042