Base | Representation |
---|---|
bin | 11110010011111110100001… |
… | …101010010001100000110111 |
3 | 122111000201020221222201222002 |
4 | 132103332201222101200313 |
5 | 114433204441220122403 |
6 | 1151311410551125515 |
7 | 40036430130650543 |
oct | 3623764152214067 |
9 | 574021227881862 |
10 | 133314202114103 |
11 | 3952926566578a |
12 | 12b5122867389b |
13 | 595062436a1aa |
14 | 24cc628482a23 |
15 | 1062c1d205188 |
hex | 793fa1a91837 |
133314202114103 has 8 divisors (see below), whose sum is σ = 137770509267456. Its totient is φ = 128867635524600.
The previous prime is 133314202114097. The next prime is 133314202114133. The reversal of 133314202114103 is 301411202413331.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 133314202114103 - 224 = 133314185336887 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (133314202114133) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2435113133 + ... + 2435167878.
It is an arithmetic number, because the mean of its divisors is an integer number (17221313658432).
Almost surely, 2133314202114103 is an apocalyptic number.
133314202114103 is a deficient number, since it is larger than the sum of its proper divisors (4456307153353).
133314202114103 is an equidigital number, since it uses as much as digits as its factorization.
133314202114103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4870281925.
The product of its (nonzero) digits is 5184, while the sum is 29.
Adding to 133314202114103 its reverse (301411202413331), we get a palindrome (434725404527434).
The spelling of 133314202114103 in words is "one hundred thirty-three trillion, three hundred fourteen billion, two hundred two million, one hundred fourteen thousand, one hundred three".
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