Base | Representation |
---|---|
bin | 11110010011111110100001… |
… | …101010010001100011111111 |
3 | 122111000201020221222202020111 |
4 | 132103332201222101203333 |
5 | 114433204441220124203 |
6 | 1151311410551130451 |
7 | 40036430130651250 |
oct | 3623764152214377 |
9 | 574021227882214 |
10 | 133314202114303 |
11 | 39529265665951 |
12 | 12b51228673a27 |
13 | 595062436a302 |
14 | 24cc628482b27 |
15 | 1062c1d20526d |
hex | 793fa1a918ff |
133314202114303 has 8 divisors (see below), whose sum is σ = 152359867147808. Its totient is φ = 114268731835104.
The previous prime is 133314202114271. The next prime is 133314202114319. The reversal of 133314202114303 is 303411202413331.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 133314202114303 - 25 = 133314202114271 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (133314202114603) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 47218776 + ... + 49962397.
It is an arithmetic number, because the mean of its divisors is an integer number (19044983393476).
Almost surely, 2133314202114303 is an apocalyptic number.
133314202114303 is a deficient number, since it is larger than the sum of its proper divisors (19045665033505).
133314202114303 is an equidigital number, since it uses as much as digits as its factorization.
133314202114303 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 97377153.
The product of its (nonzero) digits is 15552, while the sum is 31.
Adding to 133314202114303 its reverse (303411202413331), we get a palindrome (436725404527634).
The spelling of 133314202114303 in words is "one hundred thirty-three trillion, three hundred fourteen billion, two hundred two million, one hundred fourteen thousand, three hundred three".
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