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133314202114303 = 719597397181173
BaseRepresentation
bin11110010011111110100001…
…101010010001100011111111
3122111000201020221222202020111
4132103332201222101203333
5114433204441220124203
61151311410551130451
740036430130651250
oct3623764152214377
9574021227882214
10133314202114303
1139529265665951
1212b51228673a27
13595062436a302
1424cc628482b27
151062c1d20526d
hex793fa1a918ff

133314202114303 has 8 divisors (see below), whose sum is σ = 152359867147808. Its totient is φ = 114268731835104.

The previous prime is 133314202114271. The next prime is 133314202114319. The reversal of 133314202114303 is 303411202413331.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 133314202114303 - 25 = 133314202114271 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (133314202114603) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 47218776 + ... + 49962397.

It is an arithmetic number, because the mean of its divisors is an integer number (19044983393476).

Almost surely, 2133314202114303 is an apocalyptic number.

133314202114303 is a deficient number, since it is larger than the sum of its proper divisors (19045665033505).

133314202114303 is an equidigital number, since it uses as much as digits as its factorization.

133314202114303 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 97377153.

The product of its (nonzero) digits is 15552, while the sum is 31.

Adding to 133314202114303 its reverse (303411202413331), we get a palindrome (436725404527634).

The spelling of 133314202114303 in words is "one hundred thirty-three trillion, three hundred fourteen billion, two hundred two million, one hundred fourteen thousand, three hundred three".

Divisors: 1 7 195973 1371811 97181173 680268211 19044886016329 133314202114303