13331421024111 has 12 divisors (see below), whose sum is σ = 19271074264000. Its totient is φ = 8880886064160.

The previous prime is 13331421024091. The next prime is 13331421024133. The reversal of 13331421024111 is 11142012413331.

13331421024111 is a `hidden beast` number, since 1 + 3 + 3 + 3 + 142 + 102 + 411 + 1 = 666.

It is not a de Polignac number, because 13331421024111 - 2¹⁰ = 13331421023087 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13331421024011) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 560650111 + ... + 560673888.

Almost surely, 2^{13331421024111} is an apocalyptic number.

13331421024111 is a deficient number, since it is larger than the sum of its proper divisors (5939653239889).

13331421024111 is a wasteful number, since it uses less digits than its factorization.

13331421024111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1121325326 (or 1121325323 counting only the distinct ones).

The product of its (nonzero) digits is 1728, while the sum is 27.

Adding to 13331421024111 its reverse (11142012413331), we get a palindrome (24473433437442).

The spelling of 13331421024111 in words is "thirteen trillion, three hundred thirty-one billion, four hundred twenty-one million, twenty-four thousand, one hundred eleven".