1333142144111 has 4 divisors (see below), whose sum is σ = 1364145449832. Its totient is φ = 1302138838392.

The previous prime is 1333142144053. The next prime is 1333142144123. The reversal of 1333142144111 is 1114412413331.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1333142144111 - 2¹⁴ = 1333142127727 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1333142104111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15501652796 + ... + 15501652881.

It is an arithmetic number, because the mean of its divisors is an integer number (341036362458).

Almost surely, 2^{1333142144111} is an apocalyptic number.

1333142144111 is a deficient number, since it is larger than the sum of its proper divisors (31003305721).

1333142144111 is an equidigital number, since it uses as much as digits as its factorization.

1333142144111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 31003305720.

The product of its digits is 3456, while the sum is 29.

Adding to 1333142144111 its reverse (1114412413331), we get a palindrome (2447554557442).

The spelling of 1333142144111 in words is "one trillion, three hundred thirty-three billion, one hundred forty-two million, one hundred forty-four thousand, one hundred eleven".