Base | Representation |
---|---|
bin | 11110010100000101111000… |
… | …101001101111011110010011 |
3 | 122111001110122122212100011112 |
4 | 132110011320221233132103 |
5 | 114433322132113342121 |
6 | 1151315155025003535 |
7 | 40040130011152403 |
oct | 3624057051573623 |
9 | 574043578770145 |
10 | 133322104043411 |
11 | 3953165003a178 |
12 | 12b52872a835ab |
13 | 59512b34939ca |
14 | 24ccb77adc803 |
15 | 1063031ccc75b |
hex | 794178a6f793 |
133322104043411 has 8 divisors (see below), whose sum is σ = 133426101228624. Its totient is φ = 133218116896480.
The previous prime is 133322104043407. The next prime is 133322104043503. The reversal of 133322104043411 is 114340401223331.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 133322104043411 - 22 = 133322104043407 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (133322104013411) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 24174101 + ... + 29172441.
It is an arithmetic number, because the mean of its divisors is an integer number (16678262653578).
Almost surely, 2133322104043411 is an apocalyptic number.
133322104043411 is a deficient number, since it is larger than the sum of its proper divisors (103997185213).
133322104043411 is a wasteful number, since it uses less digits than its factorization.
133322104043411 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5019141.
The product of its (nonzero) digits is 20736, while the sum is 32.
Adding to 133322104043411 its reverse (114340401223331), we get a palindrome (247662505266742).
The spelling of 133322104043411 in words is "one hundred thirty-three trillion, three hundred twenty-two billion, one hundred four million, forty-three thousand, four hundred eleven".
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