13332323400001 has 4 divisors (see below), whose sum is σ = 14034024631600. Its totient is φ = 12630622168404.

The previous prime is 13332323399959. The next prime is 13332323400023. The reversal of 13332323400001 is 10000432323331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13332323400001 - 2¹³ = 13332323391809 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13332323400091) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 350850615771 + ... + 350850615808.

It is an arithmetic number, because the mean of its divisors is an integer number (3508506157900).

Almost surely, 2^{13332323400001} is an apocalyptic number.

It is an amenable number.

13332323400001 is a deficient number, since it is larger than the sum of its proper divisors (701701231599).

13332323400001 is an equidigital number, since it uses as much as digits as its factorization.

13332323400001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 701701231598.

The product of its (nonzero) digits is 3888, while the sum is 25.

Adding to 13332323400001 its reverse (10000432323331), we get a palindrome (23332755723332).

The spelling of 13332323400001 in words is "thirteen trillion, three hundred thirty-two billion, three hundred twenty-three million, four hundred thousand, one".