133325444055013 has 4 divisors (see below), whose sum is σ = 152371936062880. Its totient is φ = 114278952047148.

The previous prime is 133325444054989. The next prime is 133325444055017. The reversal of 133325444055013 is 310550444523331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 133325444055013 - 2⁹ = 133325444054501 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (133325444055017) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (31) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9523246003923 + ... + 9523246003936.

It is an arithmetic number, because the mean of its divisors is an integer number (38092984015720).

Almost surely, 2^{133325444055013} is an apocalyptic number.

It is an amenable number.

133325444055013 is a deficient number, since it is larger than the sum of its proper divisors (19046492007867).

133325444055013 is an equidigital number, since it uses as much as digits as its factorization.

133325444055013 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 19046492007866.

The product of its (nonzero) digits is 1296000, while the sum is 43.

Adding to 133325444055013 its reverse (310550444523331), we get a palindrome (443875888578344).

The spelling of 133325444055013 in words is "one hundred thirty-three trillion, three hundred twenty-five billion, four hundred forty-four million, fifty-five thousand, thirteen".