133330024111421 has 4 divisors (see below), whose sum is σ = 133330361276700. Its totient is φ = 133329686946144.

The previous prime is 133330024111399. The next prime is 133330024111441. The reversal of 133330024111421 is 124111420033331.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 52491691363225 + 80838332748196 = 7245115^2 + 8991014^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-133330024111421 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (133330024111441) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 167988776 + ... + 168780593.

It is an arithmetic number, because the mean of its divisors is an integer number (33332590319175).

Almost surely, 2^{133330024111421} is an apocalyptic number.

It is an amenable number.

133330024111421 is a deficient number, since it is larger than the sum of its proper divisors (337165279).

133330024111421 is an equidigital number, since it uses as much as digits as its factorization.

133330024111421 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 337165278.

The product of its (nonzero) digits is 5184, while the sum is 29.

Adding to 133330024111421 its reverse (124111420033331), we get a palindrome (257441444144752).

The spelling of 133330024111421 in words is "one hundred thirty-three trillion, three hundred thirty billion, twenty-four million, one hundred eleven thousand, four hundred twenty-one".