13333044111421 has 4 divisors (see below), whose sum is σ = 14034783275200. Its totient is φ = 12631304947644.

The previous prime is 13333044111407. The next prime is 13333044111503. The reversal of 13333044111421 is 12411144033331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13333044111421 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13333044111721) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 350869581861 + ... + 350869581898.

It is an arithmetic number, because the mean of its divisors is an integer number (3508695818800).

Almost surely, 2^{13333044111421} is an apocalyptic number.

It is an amenable number.

13333044111421 is a deficient number, since it is larger than the sum of its proper divisors (701739163779).

13333044111421 is an equidigital number, since it uses as much as digits as its factorization.

13333044111421 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 701739163778.

The product of its (nonzero) digits is 10368, while the sum is 31.

Adding to 13333044111421 its reverse (12411144033331), we get a palindrome (25744188144752).

The spelling of 13333044111421 in words is "thirteen trillion, three hundred thirty-three billion, forty-four million, one hundred eleven thousand, four hundred twenty-one".