1333320231001 has 4 divisors (see below), whose sum is σ = 1454531161104. Its totient is φ = 1212109300900.

The previous prime is 1333320230971. The next prime is 1333320231011. The reversal of 1333320231001 is 1001320233331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1333320231001 - 2¹⁷ = 1333320099929 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1333320231011) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 60605465035 + ... + 60605465056.

It is an arithmetic number, because the mean of its divisors is an integer number (363632790276).

Almost surely, 2^{1333320231001} is an apocalyptic number.

1333320231001 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

1333320231001 is a deficient number, since it is larger than the sum of its proper divisors (121210930103).

1333320231001 is a wasteful number, since it uses less digits than its factorization.

1333320231001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 121210930102.

The product of its (nonzero) digits is 972, while the sum is 22.

Adding to 1333320231001 its reverse (1001320233331), we get a palindrome (2334640464332).

The spelling of 1333320231001 in words is "one trillion, three hundred thirty-three billion, three hundred twenty million, two hundred thirty-one thousand, one".