Base | Representation |
---|---|
bin | 11000110101011100… |
… | …01000100101100101 |
3 | 1021102012202220110111 |
4 | 30122232020211211 |
5 | 204301300001201 |
6 | 10043012453021 |
7 | 651260233555 |
oct | 143256104545 |
9 | 37365686414 |
10 | 13333203301 |
11 | 5722277a90 |
12 | 270131a171 |
13 | 1346426812 |
14 | 906b03165 |
15 | 53081db51 |
hex | 31ab88965 |
13333203301 has 4 divisors (see below), whose sum is σ = 14545312704. Its totient is φ = 12121093900.
The previous prime is 13333203287. The next prime is 13333203313. The reversal of 13333203301 is 10330233331.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 13333203301 - 233 = 4743268709 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13333203361) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 606054685 + ... + 606054706.
It is an arithmetic number, because the mean of its divisors is an integer number (3636328176).
Almost surely, 213333203301 is an apocalyptic number.
13333203301 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
It is an amenable number.
13333203301 is a deficient number, since it is larger than the sum of its proper divisors (1212109403).
13333203301 is a wasteful number, since it uses less digits than its factorization.
13333203301 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1212109402.
The product of its (nonzero) digits is 1458, while the sum is 22.
Adding to 13333203301 its reverse (10330233331), we get a palindrome (23663436632).
The spelling of 13333203301 in words is "thirteen billion, three hundred thirty-three million, two hundred three thousand, three hundred one".
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