Base | Representation |
---|---|
bin | 1100001000000110000100… |
… | …1111110001011011000011 |
3 | 1202012122100022220221010021 |
4 | 3002001201033301123003 |
5 | 3221422403230330311 |
6 | 44205105255314311 |
7 | 2544202242100360 |
oct | 302014117613303 |
9 | 52178308827107 |
10 | 13333210011331 |
11 | 4280645501051 |
12 | 15b409507b997 |
13 | 759415c146b2 |
14 | 34148ba45467 |
15 | 181c62699171 |
hex | c20613f16c3 |
13333210011331 has 8 divisors (see below), whose sum is σ = 15238242833760. Its totient is φ = 11428249322688.
The previous prime is 13333210011313. The next prime is 13333210011337. The reversal of 13333210011331 is 13311001233331.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 13333210011331 - 219 = 13333209487043 is a prime.
It is a super-3 number, since 3×133332100113313 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 13333210011296 and 13333210011305.
It is not an unprimeable number, because it can be changed into a prime (13333210011337) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 17636776 + ... + 18377221.
It is an arithmetic number, because the mean of its divisors is an integer number (1904780354220).
Almost surely, 213333210011331 is an apocalyptic number.
13333210011331 is a deficient number, since it is larger than the sum of its proper divisors (1905032822429).
13333210011331 is an equidigital number, since it uses as much as digits as its factorization.
13333210011331 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 36066893.
The product of its (nonzero) digits is 1458, while the sum is 25.
Adding to 13333210011331 its reverse (13311001233331), we get a palindrome (26644211244662).
The spelling of 13333210011331 in words is "thirteen trillion, three hundred thirty-three billion, two hundred ten million, eleven thousand, three hundred thirty-one".
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